Kawat sepanjang 45cm dialiri arus sebesar 7 mA. Berapa medan magnet yg memengaruhi kawat jika terjadi gaya lorentz sebesar 1,89 N .....?
whongaliem
Diketahui : l = 45 Cm = 45 x 10^-2 m I = 7 mA = 7 x 10^-3 A F = 1,89 N ditanta : medan magnet (B) jawab : F = B.I.l 1,89 = B x 45 x 10^-2 x 7 x 10^-3 1,89 = 315 x 10^-5 x B B = 1,89 / (315 x 10^-5) B = {(189 x 10^-2) x 10^5} / 315 B = (189 x 10³) / 315 B = 600 T
I = 7 mA = 7 x 10^-3 A
F = 1,89 N
ditanta : medan magnet (B)
jawab :
F = B.I.l
1,89 = B x 45 x 10^-2 x 7 x 10^-3
1,89 = 315 x 10^-5 x B
B = 1,89 / (315 x 10^-5)
B = {(189 x 10^-2) x 10^5} / 315
B = (189 x 10³) / 315
B = 600 T