Kamień spada z dachu w czasie 2 s. Oblicz wysokość budynku. Jak to zrobić.?
zad1dane:t=2sg=10 m/s2szukane:h=?h=gt2/2h=10m/s2 *4s2 /2h=20modp:kamień spadł z wysokości 20m
Ek = Ep
więc
0,5 m *v^2 = m*g*h
m*v^2 = 2 m*g*h / : m
v^2 = 2 g*h
h = v^2 : ( 2 g)
==============
oraz v = g*t = 10 m/s^2 * 2 s = 20 m/s
-------------------------------------------------
czyli
h = [ 20 m/s]^2 : [ 2 *10 m/s^2] = 400 m^2/s^2 : 20 m/s^2 = 20 m
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zad1
dane:
t=2s
g=10 m/s2
szukane:
h=?
h=gt2/2
h=10m/s2 *4s2 /2
h=20m
odp:kamień spadł z wysokości 20m
Ek = Ep
więc
0,5 m *v^2 = m*g*h
m*v^2 = 2 m*g*h / : m
v^2 = 2 g*h
h = v^2 : ( 2 g)
==============
oraz v = g*t = 10 m/s^2 * 2 s = 20 m/s
-------------------------------------------------
czyli
h = [ 20 m/s]^2 : [ 2 *10 m/s^2] = 400 m^2/s^2 : 20 m/s^2 = 20 m
=============================================================