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Verified answer
AB = √[(4 - 0)² + (-2 - 2)²]AB = √(16 + 16)
AB = √32
AB = 4√2
BC = √[(0 - 4)² + (-2 + 2)²]
BC = 4
AC = √[(0 - 0)² + (-2 - 2)²]
AC = 4
Karena BC + AC > AB , maka ABC suatu segitiga
Karena BC² + AC² = AB , maka ABC adalah segitiga siku²