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Karena mno =3x dan lko=2x
Jumlah sudut segitiga = 180 sudut o = 90
3x+2x = 180-90
5x = 90
X= 18
mno = 54
Klm = 2mno
klm = 2 * 54
klm = 108
∠MNO = ∠ONK
∠KON = 90°
maka
∠OKN : ∠ONK = 2 : 3
msial : ∠OKN = 2x, ∠ONK = 3x
maka
∠OKN + ∠ONK + ∠KON = 180
⇒ 2x + 3x + 90 = 180
⇒ 5x = 90
⇒ x = 90/5
⇒ x = 18°
maka
∠KLM = 2 × ∠ONK
= 2 × 3x
= 6x
= 6(18)
= 108°
Jawab : D
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