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x² - 5x + 3 = 0
a = 1 , b = - 5, c = 3
α+β = -b/a = -(-5)/1 = 5
α. β = c/a = 3/1 = 3
PK baru akarnya p dan q
p = α-2
q = β- 2
p+q = α+β- 4 = (5-4) = 1
p q = (α-2)(β-2) = αβ- 2(α+β) + 4
p q = (3) - 2(5)+ 4
p q = 3 -10 + 4
p q = - 3
PK baru x² - (p+q) x + (p q) = 0
x² - (1) x + (-3)= 0
x² - x - 3 = 0
4. ada dilampiran