Question

Kak tolong bantu ngerjain tugas nomor 22

Answer 1

Oh tuhan jarimu itu bikin,,,,,

Answer 2

(i + j)/√2 = (1/√2)i + (1/√2)j
panjangnya = √[(1/√2)^2 + (1/√2)^2] = √(1/2 + 1/2) = √1 = 1

(cos a) i - (sin a) j panjangnya = √[(cos a)^2 + (sin a)^2] = √1 = 1