Question

KAK TOLONG BANTU JAWAB TUGASKU
RALAT
YG DIKERJAKAN HANYA NO 7, 8, 13 ,DAN 15​

Answer 1

Jawaban:

7. T = (273 + 27) K

= 300 derajat K

P = 2 atm.

R = 0,082

a. n = 0,25

V = nRT/P

V = 0,25.0,082.300/2

V = 3,075 liter

b. n = 3,75 mol

V = nRT/P

V = 3,75.0,082.300/2

V = 46,125 liter

8. 400 derajat K

P = 3 atm

a. V = nRT / P

5,6 = n.0,082.400/3

5,6 = 10,94n

n = 5 mol.

Massa

= n x Mr

= 5 x 44

= 220 gram.

b. V = nRT/P

11,2 = n.0,082.400/3

11,2 = 10,94n

n = 1 mol.

Massa

= n x Mr

= 1 x 17

= 17 gram

9. Mr CO₂ = 44

n CO₂ = gr/Mr = 22/44 = 0,5 mol

n CO₂ / V CO₂ = n O₂ / V O₂

0,5 / 10 = n O₂ / 50

n O₂ = 2,5 mol

massa O₂ = mol x Mr O₂ = 2,5 x 32 = 80 gram

10. Diketahui :

n N2 (Gas nitrogen) = 1 mol

V N2 = 25 L

P dan T sama

Ditanya : Volume ?

Jawab :

Mencari Vm (Volume molar) :

= V (N2) / n

= 25 L / 1 mol

= 25 L/mol

A.Diketahui :

n gas Metana (CH4) = 2 mol

Vm = 25 L/mol

Jawab :

Volume CH4 :

= n . Vm

= 2 mol . 25 L/mol

= 50 L

B.Diketahui :

w Amonia (NH4OH) = 34 gram

Vm = 25 L/mol

Jawab :

Mr NH4OH :

= Ar N + Al.Ar H + Ar O + Ar H

= 14 g/mol + 4 .1 g/mol + 16 g/mol + 1 g/mol

= 35 g/mol

n (mol) NH4OH :

= w / Mr

= 34 gram / 35 gram/mol

= 0,97 mol

Volume NH4OH :

= n . Vm

= 0,97 mol . 25 L/mol

11. mol N2

= massa / 2xArN

= 7 / 28

= 0,25 mol.

mol X

= massa / Mr X

= 2,2 / Mr X

mol N2 / vol N2 = mol x / vol x

0,25 / 5 = (2,2/Mr X) / 1

11 /  Mr X = 0,25

11 = 0,25 Mr X

Mr X = 44

12. V NO = 6 liter

massa NO = 7,5 gr

Mr NO = 30

V SO2 = 48 liter

Mr SO2 = 64

V NO / mol NO = V SO2 / mol SO2

6 / (7,5/30) = 48 / (x/64)

x = 48 x 64 x 7,5 / (30 x 6)

x = 128

massa SO2 = 128 gram

13. M = gr/Mr × 1000/volume

0,5 = gr / 60 ×1000 / 200

0,5 =gr / 60 × 5

30 = 5gr

 gr = 30/5

 gr = 6 gram

jadi urea yang dibutuhkan untuk membuat 200 ml larutan urea 0,5 M adalah sebanyak 6 gram

14. Volume larutan NaCl = 400 ml = 0,4 L

Molaritas NaCl = 0,25 M = 0,25 mol/L

Ar Na = 23 , Cl = 35,5

Ditanya : Berapa gram NaCl ?

Jawab :

Untuk mencari gram , NaCl yang kita butuhkan adalah mol NaCl dan Mr NaCl , nya sehingga kita baru bisa mentukan massa nya.

Langkah :

n NaCl :

= M . V

= 0,25 mol/L . 0,4 L

= 0,1 mol

Mr NaCl :

= Ar Na + Ar Cl

= 23 + 35,5

= 58,5 gram/mol

Massa NaCl :

= n . Mr

= 0,1 mol . 58,5 gram/mol

= 5,85 gram

15. M = gr/Mr x 1000/v(ml)

=2/40 x 1000/100

=1/20 x 10

=0.5 M