Question

Kak, tolong bantu jawab dong nomor 5&6 dengan penyelesaian....
besok dikumpul nih kak

Answer 1

Trigonometri

5) y =  1/6 { cos 6t + cos 3t }

y = 1/6 { 2 cos 1/2 (6t + 3t) cos 1/2 (6t - 3t)}

y =  2/6 { cos  (9t/2) cos (3t/2) }

y = 1/3 { cos (9t/2)  cos (3t/2)}

Nilai  Ampitudo = 1/3

nilai Maks = A = 1/3

nilai min = - A = - 1/3

*

6) y1 =  A sin (ωt - kx)

y2  = A sin (ωt + kx)

misal Y = y1 + y2

y = A sin (ωt - kx) + A sin (ωt + kx)

y = A { sin (ωt - kx) +  sin (ωt + kx) }

y = A {  2 sin 1/2 [ (ωt - kx) + (ωt + kx)]  cos 1/2 [ (ωt - kx) - (ωt + kx)]

y = A { 2 sin 1/2 (2ωt)  cos 1/2 (- 2kx)}

y =  2A { sin ωt  cos (-kx) }

y = 2 A sin (ωt) cos (kx)