Question

Kak soal integral lagi

Answer 1

Verified answer

Materi integral trigonometri <<<

Answer 2

Verified answer

A•

teta = a
dcos 2a = -2 sin 2a da

∫2sin 2a da [60°...30°]
= - ∫dcos 2a
= -cos 2a
= -cos 120° + cos 60°
= 1/2 + 1/2
= 1

b•

∫3 sin t dt [2...0]
= -3 ∫dcos t
= -3 cos t
= -3 (cos 2 - cos 0}
= -3( cos (2 × 180/3,14) - cos 0)
= -3( -0,417 - 1)
= -3 × (-1,417)
= 4,251