" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
1)diketahui :
x²+px-(p+1) = 0
a = 1 , b = p dan c = -(p+1)
A + B = -b/a = -p
A×B = c/a = -(p+1)
A²+B² = 50
(A+B)² -2AB = 50
(-p)²+2(p+1) = 50
p² + 2p + 2 -50 = 0
p²+2p -48 = 0
(p+8)(p-6) = 0
p= -8 atau p = 6
2)
diketahui :
x²+(p+1)x + 2-p = 0
a = 1 , b = p+1 dan c = 2-p
akar² tdak real maka
b²-4ac <0
(p+1)²-4(2-p)<0
p²+2p+1 +4p -8 <0
p² + 6p -7<0
(p+7) (p-1)<p
p= -7 atau p = 1
karena kurang dari "<" maka
p<-7 atau p > 1
note : A = alfa, B = Beta