Question

Kak mohon bantuanya saya mohon

Answer 1

Verified answer

a. 20 s

b. 800 m

c. 20 m/s

Penjelasan:

a. selang waktu PQ

s = 400 m

v = 20 m/s

Maka selang waktu di PQ

t = s/v

= 400/20

= 20 s

b. jarak

= 400 m + 20 x 20

= 400 + 400

= 800 m

c. s = 800 m

t = 20 s + 20 s

= 40 s

v = s/t

= 800/40

= 20 m/s

Answer 2

Kecepatan, Jarak, dan Perpindahan

..

Diberikan

• PQ 20 m/s
• PQ 400 meter
• QR 20s
• QR 20 m/s

Tentukan

• selang PQ
• jarak P-Q-R
• v rata-rata P-Q-R

Hasil dan Perhitungan

[tex]selang~PQ = \frac{400}{20} [/tex]

[tex]~~~~~~~~~~~~~~~~~~~~=20 \: sekon[/tex]

..

[tex]jarak~PQR = 400 + (20 \times 20)[/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~=400 + 400[/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~=800 \: meter[/tex]

..

[tex]v~rata-rata = \frac{20 + 20}{2} [/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~~~~= \frac{40}{2} [/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~~~~= 20~m/s[/tex]

..

[tex]\begin{array}{lr}\texttt{Rate 1.0 Jika Kalian Iri dengan}\\\\ \texttt{Yang Mulia Maharaja Danial Alf'at}\end{array}[/tex] ☝️

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at}}\boxed{\colorbox{ccddff}{13/03/23}}[/tex]