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maka pH= 5
M=n/V n=M×v
CH3COOH + KOH --> CH3COOK + H2O
M 0,2×0,1=0,02 0,05×0,2=0,01 Dikurangi reaksi pembatas: KOH
r 0,01 0,01 0,01
s 0,01 0 0,01
Rumus penyangga asam
H^+=KA×na/nbk
=10^-5×0,01÷0,01
=10^-5
pH= 5