Question

Kak ini pembahasannya gimana ya?

Answer 1

Misal : u = x → du = dx
dv = √x-2 = (x-2)^1/2
v = integrl (x-2)^1/2
= 2/3.(x-2)^3/2
↓
15 . intgral u.dv =15( u.v - intgral v.du)
→ = 15 { x. 2/3.(x-2)^3/2 - intgrl 2/3.(x-2)^3/2. dx }
= 15 { x. 2/3.(x-2)^3/2 - 2/3.2/5.(x-2)^5/2 } batas 2 smpai 3
= 15 [ { 3. 2/3. (3-2)^3/2 - 2/3. 2/5. (3-2)^5/2} - { 0 } ]
= 15 { 3. 2/3. 1 - 2/3. 2/5. 1}
= 15 { 2 - 4/15}
= 15 { (30-4)/15 }
= 15 { 26/15}
= 26
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