Jawab:
induksi matematika
Penjelasan dengan langkah-langkah:
buktikan
1 + 3 + 5 + ...+ (2n - 1) = n²
an = 2n - 1
ak = 2k - 1
a(k+1) = 2(k +1)- 1 = 2k + 1
pn = n²
pk = k²
p(k+1) = (k+ 1)² = k²+2k + 1
.
akan dibuktikan bahwa
p(k+1) = pk + a(k+1)
k² +2k + 1 = k²+2k + 1
terbukti
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Jawab:
induksi matematika
Penjelasan dengan langkah-langkah:
buktikan
1 + 3 + 5 + ...+ (2n - 1) = n²
an = 2n - 1
ak = 2k - 1
a(k+1) = 2(k +1)- 1 = 2k + 1
pn = n²
pk = k²
p(k+1) = (k+ 1)² = k²+2k + 1
.
akan dibuktikan bahwa
p(k+1) = pk + a(k+1)
k² +2k + 1 = k²+2k + 1
terbukti