Ka tlng bntu jwb yahpake cara,yang nomor 1&2 bagian a gausah dijawab. mksh sblumnya
subebe
1.b jarak T ke rusuk alas = √ (1/2 x 12)² + 8²) = √(6² + 8²) = √(36 + 64) = √100 = 10 cm c. Luas permukaan = 12 x 12 + 4 (1/2 x 10 x 12) = 144 + 4 (60) = 144 + 240 = 384 cm²
2. a. 1/2 rusuk alas = √(17² - 15²) = √(289 - 225) = √64 = 8 rusuk alas = 2 x 8 = 16 cm b. luas permukaan = 16 x 16 + 4 (1/2 x 17 x 16) = 256 + 4 (136) = 256 + 544 = 800 cm²
= √(6² + 8²) = √(36 + 64)
= √100 = 10 cm
c. Luas permukaan = 12 x 12 + 4 (1/2 x 10 x 12)
= 144 + 4 (60)
= 144 + 240
= 384 cm²
2. a. 1/2 rusuk alas = √(17² - 15²)
= √(289 - 225)
= √64
= 8
rusuk alas = 2 x 8 = 16 cm
b. luas permukaan = 16 x 16 + 4 (1/2 x 17 x 16)
= 256 + 4 (136) = 256 + 544
= 800 cm²