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Verified answer
Materi : Persamaan EksponenPembahasan :
(x + 4)^(x - 1) = (x + 4)^(x² - 7x + 6)
Syarat pertama
x - 1 = x² - 7x + 6
x² - 8x + 7 = 0
(x - 7)(x - 1) = 0
x = 1
x = 7
Syarat Kedua
x + 4 = 1
x = 1 - 4
x = -3
Syarat Ketiga
x + 4 = -1
x = -1 - 4
x = -5 ※Memenuhi※
Syarat Keempat
x + 4 = 0
x = -4 ※Tidak memenuhi※
Hp : {-5 , -3 , 1 , 7}