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Bilangan bulat antara 100 dan 300 habis dibagi 5
105, 110, 115, 120,...., 295
a = 105
b = 5
Uₙ = 295
→ banyak suku
Uₙ = 295
a + (n - 1)b = 295
105 + (n - 1)(5) = 295
105 + 5n - 5 = 295
5n = 295 - 100
5n = 195
n = 195/5
n = 39
→ Jumlah bilangan
S₃₉ = n/2 (a + Uₙ)
S₃₉ = 39/2 (105 + 295)
S₃₉ = 39/2 (400)
S₃₉ = 39 x 200
S₃₉ = 7800 ✔
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• Kelas : IX
• Mapel : Matematika
• Kategori : Barisan dan Deret Bilangan
• Kata Kunci : Deret Aritmatika