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124= 4 (p+l+t)
124= 4 (15+10+t)
124= 100 + 4t
24= 4t
t= 6 cm
b. luas permukaan
lp= 2 x (p*l + l*t + p*t)
=2 (15*10 + 10*6 + 15*6)
=2 (150+60+90)
=2 (300)
=600
c. volume
v= p.l.t
=15*10*6
=900
p = 15 cm
l = 10 cm
Jumlah rusuk = 4 ( p + l + t )
124 = 4 ( 15 + 10 + t )
124 = 60 + 40 + 4t
124 = 100 + 4t
124-100 = 4t
t = 24/4
t = 6 cm
Tinggi balok = 6 cm
Lp = 2 ( pl + pt + lt )
= 2 ( 15.10 + 15.6 + 10.6 )
= 2 ( 150 + 90 + 60 )
= 2 ( 300 )
= 600 cm²
Luas Permukaan balok = 600 cm²
V = p x l x t
= 15 x 10 x 6
= 900 cm³
Volome balok = 900 cm³