Jumlah 5 suku pertama suatu barisan geometri adalh 93 . jika rasio barisan tersebut adalh 2 maka suku ke 6 barisan tersebut adalh a . 48 b . 60 c . 96 d , 100
subebe
S5 = a (r^5 - 1) / (r-1) 93 = a (2^5 - 1) / (2 - 1) 93 = a (32 - 1) 93 = a (31) a = 3 U6 = ar^5 = 3 (2)^5 = 3 (32) = 96 (C)
93 = a (2^5 - 1) / (2 - 1)
93 = a (32 - 1)
93 = a (31)
a = 3
U6 = ar^5 = 3 (2)^5 = 3 (32) = 96 (C)