Jumlah 3 bilangan ganjil berurutan adalah 45.Jumlah bilangan terbesar dan terkecil dari ketiga bilangan tersebut adalah... a.26 b.30 c.34 d.38 JAWAB dengan CARANYA
imeldarita
A + a + 2 + a + 4 = 45 3a + 6 = 45 3a = 39 a = 13 Terkecil = a = 13 Terbesar = a + 4 = 13 + 4 = 17 Jumlah = 13 + 17 = 30 (B)
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Beta27
U1 = a = x U2 = a + b = x + 2 U3 = a + 2b = x + 2(2) = x +4
45 = x + x + 2 + x + 4 45 = 3x + 6 45-6 = 3x 39 = 3x x = 39/3 x = 13
terkecil + terbesar = x + x + 4 = 13 + 13 + 4 = 13 + 17 = 30 (B)
3a + 6 = 45
3a = 39
a = 13
Terkecil = a
= 13
Terbesar = a + 4
= 13 + 4
= 17
Jumlah = 13 + 17
= 30 (B)
U2 = a + b = x + 2
U3 = a + 2b = x + 2(2) = x +4
45 = x + x + 2 + x + 4
45 = 3x + 6
45-6 = 3x
39 = 3x
x = 39/3
x = 13
terkecil + terbesar = x + x + 4 = 13 + 13 + 4 = 13 + 17 = 30 (B)