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4(j-4) = r+4
r = j+2+2 = j+4
4(j-4) = j+4+4
4j - 16 = j+8
4j-j = 8+16
3j = 24
j = 24/3
j = 8
r = j+4
r = 8+4
r = 12
comprobación:
4(j-4) = r+4
4(8-4) = 12+4
4*4 = 16
Respuesta:
cada uno tiene:
Juan: 8 cuadernos
Ricardo: 12 cuadernos