Question

Jika x = 3log2, maka √(27^x + 8 . 3^x+2) = ....?

Answer 1

X = 3 log 2
3^x = 2

√(27^x + 8 . 3^x + 2)
= √[(3^3)^x + 8 . 3^x + 2]
= √[(3^x)^3 + 8 . 3^x + 2]

Selanjutnya, ganti (substitusi) 3^x dengan 2
Maka diperoleh:

= √(2^3 + 8 . 2 + 2)
= √(8 + 8 . 2 + 2)
= √(8 + 16 + 2)
=√26


Semoga membantu :)

Answer 2

Semoga Membantu √