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Langkah pertama subs. x=-3 ke pers. x²+(c+6)x-5=0→(-3)²+(c+6)x-5=0
→9+c+6-5=0
→10+c=0
→c=-10
∴ x²+(c+6x)-5=0
x²+(-10+6)x-5=0
x²-4x-5+=0
(x-5)(x+1)=0
x₁ = 5 ∨ x₂ = -1
maka akar lain dari pers. tsb. x₁ = 5 dan x₂ =-1