Question

Jika volume kerucut 96 cm,panjang jari jari alas nya 6cm,tentukan luas selimut kerucut!

Answer 1

V= phi * 1/3 * r^2 * t
96 = 3,14 * (1/3) * 6^2 *t
96 = 37,68t
t=2,54

S^2=r^2 + t^2
     = 6*6 + 2,54*2,54
     = 36 + 6,45
S^2= 42,45
S  = akar 42,45
S = 6,51

Luas selimut = phi * R * S
                     = 3,14 * 6 * 6,51
                     = 122,64

Answer 2

V=96, r=6
V= 1/3. . r2. t
96=1/3.3,14.36.t
t=96/(12.3,14)
t=2,55

Ls= .r.s            s=√r2 + t2 = √36 + 6,76 = 6,5
    = 3,14.6.6,5
   = 122,46