Question

Jika titik A (4, 2, q), B (2, -2, 1) dan C (8, p+3, -8) segaris, nilai p+q = ....

Answer 1

Verified answer

Dik
vektor a,b,c:
a=(4 2 q)
b=(2 -2 1)
c=(8 p+3 -8)
titik segaris, maka vektornya akan saling berkelipatan:
AB=k.AC
b-a=k(c-a)
(-2 -4 1-q)=k(4 p+1 -8-q)
didapat:
-2=4k >>> k=-1/2
-4=k(p+1) >>> -4=-½(p+1) >>> p=7
1-q=k(-8-q) >>> 1-q=-½(-8-q) >>> 2-2q=8+q >>> q=-2

~jadi nilai p+q=7+(-2)=5