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maka
sin(α-β) = sin(π/6)
sinαcosβ - cosαsinβ = 1/2
1/3 - cosαsinβ = 1/2
cosαsinβ = 1/3 - 1/2
cosαsinβ = -1/6
so,
sin(α+β)
= sinαcosβ + cosαsinβ
= 1/3 + (-1/6)
= 1/6
-2 sinA.SinB = cos(A+B) - cos(A-B)
-2 (1/3) = cos(A+B) - cos(π/6)
-2/3 = cos(A+B) - 1/2(√3)
cos(A+B) = √3/2 - 2/3 = = [Buat segitiganya]
depan =
=
=
=
sin(A+B) =
=
kok rasanya, jelek ya angkanya ~~?
ada yg salah ga?