Question

Jika P(n,4) =30C(n,5),nilai P(n,1)adalah
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Answer 1

Penyelesaian

P(n,4) =30C(n,5)
n ! / (n-4)! = 30× n ! / [5! (n-5)!)
{ n ! / (n-4)! = 30× n ! / [5! (n-5)!) } × 1/n,2n,n!
1 / (n-4)! = 30× 1 / [5! (n-5)!)
5!(n-5)! = 30 (n-4 )!
60(n-5)! = 30 (n-4 )!

60× 1×2×3×...×(n-5)
= 30×1×2×3×...×(n-5)(n-4)

60× [1×2×3×...×(n-5)]
= 30 × [ 1×2×3×...×(n-5) ](n-4)

60 = 30 ×( n-4)
60= 30n -120
30n = 180
n = 180/30
n = 6

karena n=6 ---> P(n,1)= P(6,1) = 6!/5! = 6

Jawab
Jika P(n,4) =30C(n,5),nilai P(n,1) adalah 6



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