Penjelasan dengan langkah-langkah: Diketahui persegi panjang Panjang CD (p) = 12 cm Luas persegi panjang (a) = 60 cm²
Lebar AB (l) = a/p = 60 cm² / 12 cm = 5 cm Lebar AB (l) = 5 cm
Diketahui lingkaran (r-x) = 2 cm
Menggabungkan elemen persegi panjang tadi 2(r+x) = l 2(r+x) = 5 r + x = 5/2 x = (5/2) - r
Cari nilai r dulu (r-x) = 2 cm r-((5/2) - r) = 2 r- (5/2) + r = 2 2r - (5/2) = 2 2r = 2 + (5/2) 2r = (4/2) + (5/2) 2r = 9/2 r = 9/(2(2)) r = 9/4
Lalu cari nilai x (r-x) = 2 cm (9/4) - x = 2 x = (9/4) - 2 x = (9/4) - (8/4) x = 1/4
Lalu cari luas kuning Luas kuning = setengah dari (luas persegi panjang - luas lingkaran) Luas kuning = (1/2) · (a - πr²) {π ≈ 3,14} Luas kuning ≈ (1/2) · (60 - 3,14·(9/4²)) Luas kuning ≈ (1/2) · (60 - 3,14·(9/4)²) Luas kuning ≈ (1/2) · (60 - 3,14·(81/16)) Luas kuning ≈ (1/2) · (60 - 15,89625) Luas kuning ≈ (1/2) · 44,10375 Luas kuning ≈ 22,051875 cm²
Jawab:
c. ≈ 22 cm²
Penjelasan dengan langkah-langkah:
Diketahui persegi panjang
Panjang CD (p) = 12 cm
Luas persegi panjang (a) = 60 cm²
Lebar AB (l) = a/p = 60 cm² / 12 cm = 5 cm
Lebar AB (l) = 5 cm
Diketahui lingkaran
(r-x) = 2 cm
Menggabungkan elemen persegi panjang tadi
2(r+x) = l
2(r+x) = 5
r + x = 5/2
x = (5/2) - r
Cari nilai r dulu
(r-x) = 2 cm
r-((5/2) - r) = 2
r- (5/2) + r = 2
2r - (5/2) = 2
2r = 2 + (5/2)
2r = (4/2) + (5/2)
2r = 9/2
r = 9/(2(2))
r = 9/4
Lalu cari nilai x
(r-x) = 2 cm
(9/4) - x = 2
x = (9/4) - 2
x = (9/4) - (8/4)
x = 1/4
Lalu cari luas kuning
Luas kuning = setengah dari (luas persegi panjang - luas lingkaran)
Luas kuning = (1/2) · (a - πr²)
{π ≈ 3,14}
Luas kuning ≈ (1/2) · (60 - 3,14·(9/4²))
Luas kuning ≈ (1/2) · (60 - 3,14·(9/4)²)
Luas kuning ≈ (1/2) · (60 - 3,14·(81/16))
Luas kuning ≈ (1/2) · (60 - 15,89625)
Luas kuning ≈ (1/2) · 44,10375
Luas kuning ≈ 22,051875 cm²
Jawaban c. ≈ 22 cm²
(xcvi)