Question

Jika p dan q akar dari persamaan [y+3]^2-[y+3]3-2=0 maka nilai p dan q adalah
mohon dijawab,terimakasih

Answer 1

(y+3)² -(y+3)3 -2 = 0
misl y+3 = x

x² - 3x  - 2= 0
(x -2)(x-1)= 0
x = 2  atau x = 1
.
y+3 = x 
x = 2 --> y+3 = 2 --> y₁ = -1
x = 1 --> y+3 = 1 --> y₂ = - 2

p = y1 = -1
q = y2 = -2

p+q = -1 - 2 = - 3