Question

Jika p dan q akar dari persamaan [y+3]²-[y+3]-2=0 maka nilai p +q adalah
terimakasih teman

Answer 1

(y+3)² - ( y+3) - 2 = 0

misal y+3 = a

a² - a - 2 = 0
(a - 2)(a+1) = 0

a = 2. ; a = -1

y+3 = 2
y = -1
p = -1

y+3 = -1
y = -4
q = -4

p + q = -1 + -4 = -5