Question

Jika P= 6, G= -3 dan R = -5 hitunglah nilai dari bentuk aljabar berikut
a pg - 2gr
b 2 p pangkat2 g - 4 gr pangkat2
c ( p+g-r ) +( p-g-r )
d ( 2p - 3g - 2r ) - ( 2p + 5g - 7r )

Answer 1

A.) 6(-3)-2(-3(-5))=-18-30=-48
b.) 2(6)²(-3)-4(-3(-5)²)= -216+300 = 84
c.) (6-3+5)+(6+3+5)=8+14=22
d.) (2(6)-3(-3)-2(-5))-(2(6)+5(-3)-7(-5)) = 12+9+10-12-15+35 = 39
maaf kalo salah matanya udah sepet

Answer 2

Dik: P=6 , G=-3, R=-5
a.pg-2gr
=> 6.(-3) - 2(-3.-5)
=-18 - 2(15)
=-18 -30
= -48

b. 2p^2 g - 4gr^2
=>2(6)^2 (-3) - 4(-3.-5)^2
=12^2 (-3) - 4(15)^2
= 144(-3) - 60^2
= -432 - 3600
= -4032

c.(p+g-r) + (p-g-r)
=> (6+(-3)-(-5)) + (6-(-3)-(-5))
= 8 + 14
= 22

d.(2p-3g-2r) - (2p+5g-7r)
=>(2(6)-3(-3)-2(-5)) - (2(6)+5(-3)-7(-5))
=(12-(-9)-(-10)) - (12+(-15)-(-35))
= 31 - 32
= -1