Jika konsentrasi ion h+ dalam larutan =0,0002m dan log 2= 0,3 ,maka ph larutan adalah
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![[H^+]=0,0002=2.10^{-4}~M \\ \\ pH=-log2.10^{-4} \\ \\ =4-log2 \\ \\ =4-0,3=3,7](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0%2C0002%3D2.10%5E%7B-4%7D%7EM+%5C%5C++%5C%5C+pH%3D-log2.10%5E%7B-4%7D+%5C%5C++%5C%5C+%3D4-log2+%5C%5C++%5C%5C+%3D4-0%2C3%3D3%2C7 "[H^+]=0,0002=2.10^{-4}~M \\ \\ pH=-log2.10^{-4} \\ \\ =4-log2 \\ \\ =4-0,3=3,7")
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Nengahdesy
ini bener gax?
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