Jika jangkauan dari data terurut x-1, 2x-1 ,3x,7x-3,4x+3,6x+2 adalah 8 ,maka mediannya adalah…
DB45
(x-1), (2x-1), (3x), (7x-3), (4x+3),(6x+2) banyak data = 6 J = 8 6x+2 - (x-1) = 8 6x + 2 - x + 1= 8 5x + 3 = 8 5x = 5 x = 1
Median = data tengah = data ke 1/2 (n+1) = 1/2 (6+1)= data ke 3,5 Me= 1/2(data ke 3 + data ke 4) Me = 1/2(3x + 7x-3) Me = 1/2(10x -3) dengan x= 1 --> 1/2 (10-3) = 1/2(7) = 3,5
banyak data = 6
J = 8
6x+2 - (x-1) = 8
6x + 2 - x + 1= 8
5x + 3 = 8
5x = 5
x = 1
Median = data tengah = data ke 1/2 (n+1) = 1/2 (6+1)= data ke 3,5
Me= 1/2(data ke 3 + data ke 4)
Me = 1/2(3x + 7x-3)
Me = 1/2(10x -3)
dengan x= 1 --> 1/2 (10-3) = 1/2(7) = 3,5