SISTEM BENDA m₁
T = m₁.a₁
T = 6.a₁
SISTEM BENDA m₂
F - 2T = m₂.a₂
56 - 2. 6.a₁ = 4.a₂
56 - 12.a₁ = 4.a₂
56 - 12.a₁ = 4. 1/2.a₁
56 = 14.a₁
a₁ = 56/14
a₁ = 4 m/s²
TEGANGAN TALI
T = m₁.a₁ = 6. 4
T = 24 N
Jawaban C
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SISTEM BENDA m₁
T = m₁.a₁
T = 6.a₁
SISTEM BENDA m₂
F - 2T = m₂.a₂
56 - 2. 6.a₁ = 4.a₂
56 - 12.a₁ = 4.a₂
56 - 12.a₁ = 4. 1/2.a₁
56 = 14.a₁
a₁ = 56/14
a₁ = 4 m/s²
TEGANGAN TALI
T = m₁.a₁ = 6. 4
T = 24 N
Jawaban C
a2=1/2a1
ditinjau dari benda 2
F-2T=m2×a2
56-2T=4×1/2a1
56-2T=2a1
28-T=a1
-T=a1-28
T=-a1+28.....(1)
ditinjau dari benda 1:
T=m1×a1
T=6a1......(2)
subtitusikan:
-a1+28=6a1
28=7a1
a1=4m/s²
Tegangan Tali:
T=m1×a1
=6×4
=24N