Question

Jika f(x)=3x⁴+10x³+(p+1)x+9 habis dibagi (3x+1) bersisa 7, berapakah nilai p?

Answer 1

Jadi teorima sisa  jika 3x+1=0  shg x= -1/3 maka hasilnya =7

3 (-1/3)^4+10(-1/3)^3+(p+1)(-1/3) +9 = 7

3/81 +10 (-1/27) -p/3-1/3+9=7

3/81-10/27-p/3-1/3=7-9

3/81 - 30/81 - 27/81 -p/3 = -2

-p/3= -54/81-2

p = 3(54/81+2)

p=54/27+6=2+6=8