Jika diketahui massa atom relatif h=1, s=32,o=16 dan massa molekul relatif (nh4)2so4=132 maka massa atom relatif n adalah... a.7 b.12 c.14 d.20 e.28 pakai cara ya..mksh
aryakusuma2000
Diketahui : Massa atom relatif = Ar Ar H = 1 Ar S = 32 Ar O = 16 Mr (NH4)2SO4 = 132
Ditanya : Massa atom relatif (Ar) N ?
Jawab :
• Massa atom relatif (Ar) N : (NH4)2SO4 = Mr N2H8SO4 = Mr 2.Ar N + 8.Ar H + 1.Ar S + 4.Ar O = Mr 2.Ar N + 8.1 + 1.32 + 4.16 = 132 2.Ar N + 104 = 132 2.Ar N = 132 - 104 2.Ar N = 28 Ar N = 28 / 2 Ar N = 14
Massa atom relatif = Ar
Ar H = 1
Ar S = 32
Ar O = 16
Mr (NH4)2SO4 = 132
Ditanya : Massa atom relatif (Ar) N ?
Jawab :
• Massa atom relatif (Ar) N :
(NH4)2SO4 = Mr
N2H8SO4 = Mr
2.Ar N + 8.Ar H + 1.Ar S + 4.Ar O = Mr
2.Ar N + 8.1 + 1.32 + 4.16 = 132
2.Ar N + 104 = 132
2.Ar N = 132 - 104
2.Ar N = 28
Ar N = 28 / 2
Ar N = 14
Jawaban : ( c )