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0,15 0,15 0,15
[Cl⁻] = 0,15 M
AgCl ⇆ Ag⁺ + Cl⁻
Ksp = [Ag⁺] [Cl⁻]
Ksp = [s] [0,15]
10⁻¹⁰ = 0,15s
s = 10⁻¹⁰/0,15
s = 6,67 x 10⁻¹⁰
Jadi, kelaritan AgCl dalam KCl 0,15 M adalah 6,67 x 10⁻¹⁰