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Materi : Aritmatika dan Sosial
Sub Materi : Fungsi Invers
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Cara 1 ⬇️⬇️⬇️
f(x) = x² - 2x + 1
f¯¹(4) = y
f(y)= 4
y² - 2y + 1 = 4
y² - 2y + 1 - 4 = 0
y² - 2y - 3 = 0
( y - 3 ) ( y + 1 ) = 0
y = 3 atau y = - 1
f¯¹(4) = 3 atau f¯¹(4) = - 1 ... ✔️
Cara 2 ⬇️⬇️⬇️
f(x) = x² - 2x + 1
y = x² - 2x + 1
y = (x - 1)²
√y = x - 1
(√y) + 1 = x
x = (√y) + 1
f¯¹(x) = (√x) + 1
Maka :
f¯¹(4) = (√4) + 1
f¯¹(4) = 2 + 1
f¯¹(4) = 3 ... ✔️
Semoga bermanfaat....
-Prisco