Question

Jika diketahui BO= 6 cm, Carilah luas bangun ABCDEF!

(mohon di jawab secara singkat)​

Answer 1

Jawaban:

Langkah penyelesaian:

panjang OC

[tex] \sf = \sqrt{ {10}^{2} - {6}^{2} } [/tex]

[tex] \sf = \sqrt{100 - 36} [/tex]

[tex] \sf = \sqrt{64} [/tex]

[tex] \sf = 8 \: cm[/tex]

Panjang OD

[tex] \sf = \sqrt{ {17}^{2} - {8}^{2} } [/tex]

[tex] \sf = \sqrt{289 - 64} [/tex]

[tex] \sf = \sqrt{225} [/tex]

[tex] \sf = 15 \: cm[/tex]

a = 12 cm

b = 20 cm

t = 6 cm

[tex]\sf {d}_{1}=8+8=16\:cm[/tex]

[tex]\sf {d}_{2}=6+15=21\:cm[/tex]

Luas ABCDEF

[tex] \sf =( \frac{a + b}{2} \times t) + ( \frac{ d_{1} \times d_{2} }{2} )[/tex]

[tex] \sf =( \frac{12 + 20}{2} ) + ( \frac{ \not16 {}^{8} \times 21}{ \not2} )[/tex]

[tex] \sf = ( \frac{32}{2} ) + 168[/tex]

[tex] \sf = 16 + 168[/tex]

[tex] \sf = \boxed{ \sf184 \: {cm}^{2} }[/tex]