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LP1 = 4 π r²
= 1/4 π d2²
= 1/4 π (2 d2)²
= 1/4 π 4x d2²
= π x d2²
LP2 = 1/4 π d2²
perbandingannya
LP1 : LP2
π x d2² : 1/4 π x d2² (π x d2² boleh dihapus)
1 : 1/4
4 : 1
jadi perbandingan Luas Permukaan bola 1 dan Luas Permukaan bola 2. adalah 4 : 1