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Akarnya adalah a dan b sehingga,
b = 1/a
Sehingga,
Tinjau konstantanya:
3a = 1
a = 1/3
Sehingga,
Diskriminan:
x1.x2 = 1
c/a =1
c=a
3a=1
a=1/3
x1+x2 = -b/a
=-(-2-6a) /a
=2+6a / a
=2+(6.1/3):1/3
=12
pk baru = x²-12x+1
D = b²-4ac =144-4
=140