Question

Jika AB = 12, AC = 6, dan siku2 di A.
Nilai BC adalah...​

Answer 1

Jawaban:

6√5 cm

Penjelasan dengan langkah-langkah:

Jika ABC siku-siku di A

Maka BC adalah sisi hipotenusa segitiga tersebut

BC² = AB² + AC²

BC² = 12² + 6²

BC² = 144 + 36

BC = √180

BC = √36√5

BC = 6√5 cm

#dnft

Answer 2

Diketahui :

AB = 12

AC = 6

Ditanya :

Nilai BC?

Jawab :

[tex]\sf \bf \sf BC² = AB² + AC²[/tex]

[tex]\sf \bf \sf BC² = 12² + 6²[/tex]

[tex]\sf \bf \sf BC² = (12 \times 12)+ (6 \times 6)[/tex]

[tex]\sf \bf \sf BC² = 144 + 36[/tex]

[tex]\sf \bf \sf BC² = 180[/tex]

[tex]\sf \bf \sf BC = \sqrt{180}[/tex]

[tex]\sf \bf \sf BC = \sqrt{36 \times 5}[/tex]

[tex]\sf \bf \sf BC = \sqrt{36} \times \sqrt{5}[/tex]

[tex]\sf \bf \sf BC = 6 \times \sqrt{5}[/tex]

[tex]\bold{\underline{\boxed{\pink{\sf \bf \tt BC = 6 \times \sqrt{5}}}}}[/tex]