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Jika diketahui fungsif(x) = Ax³+Bx²+Cx+D dan akar²nya adalah a,b,c .maka berlaku
a+b+c= -B/A
ab + bc + ac = C/A
abc= -D/A
m(x) = x³-3x+1
maka A=1 , B= 0 ,C =-3 dan D=1
jadi nilai a+b+c= -0/1= 0
dan nilai ab + bc + ac=-3/1=-3
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