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maka:
a³ = a + 1
b³ = b + 1
c³ = c + 1
________ +
a³ + b³ + c³ = (a + b + c) + 3
= (-(-1)/1) + 3
= 1 + 3
= 4
x³ = x + 1
krena a,b,c adalah akar2 dari persamaan ersebut. maka
a³ = a+1
b³ = b+1
c³ = c+1
jumlahkan ketiga persamaan diatas
a³ + b³ + c³ = (a+b+c) + 3
a³ + b³ + c³ = ((-0)/1) + 3
= 0 + 3
= 3