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Verified answer
Jawab1)
a³ - a - 1 = 0
a(a³ - a -1 ) = 0
a⁴ - a² - a = 0
a⁴ + a³ - a² - 2a + 1 =
= (a⁴- a² - a) + (a³- a - 1) + 2
= 0 + 0 + 2
= 2
2) 2x³ + 3x² -17x + 12 =0
x= 1 -> 2+3-17 +12 =0
x= 1 adalah faktor
dengan horner
.....2.....3....-17.....12
1...........2......5....-12
.....2.....5....-12 ....(0)
= (x- 1)(2x² + 5x -12)
= (x - 1)(x+4)(2x-3)
maka faktor nya
x - 1= 0 , x = 1
x + 4 = 0 , x = - 4
2x - 3 = 0, x = 3/2