Question

Jika a=-3 dan b=4 tentukan bentuk aljabar berikut:
a.4a+3b²=
b.5b²-3ab+2a=
c.6a²b+3ab-4a=
d.-5ab+4a²+5b=
e.7b+4a²-5b=


Tolong bantu ya kak

Answer 1

A. 4a+3b^2 = 4(-3)+3(4)^2 = -12+3(16) = -12+48 = 36
b. 5b^2-3ab+2a = 5(4)^2-3(-3)(4)+2(-3) = 5(16)-36+6 = 80-36+6 = 110
c. 6a^2b+3ab-4a = 6(-3)^2(4)+3(-3)(4)-4(-3) = 24(9)+36+12 = 216+36+12 = 264
d. -5ab+4a^2+5b = -5(-3)(4)+4(-3)^2+5(4) = 15(4)+4(9)+9 = 60+36+9 = 105
e. 7b+4a^2-5b = 7(4)+4(-3)^2-5(4) = 28+4(9)-20 = 8+36 = 44

Terima Kasih,, tolonh jadikan jawaban ini sebagai "solusi terbaik"

Answer 2

A. 4.-3 + 3.4² = -12 + 3.16 = -12 + 48 = 36                                                           b. 5.4² - 3.(-3.4) +2.-3 =5.16 - 3.-12 -6 = 80 + 36 -6 =110                                     c. (6.-3².4) +(3.-3.4)- 4.-3 =6.9.4 + 3.-12  +12 = 216 -36  + 12 = 192                     d.(-5.-3.4) + (4.-3²) + (5.4) = 15.4  + 4.9 + 20 = 60  + 36 +20 = 116                       e. 7.4 +  4.-3² -5.4 = 28 + 4.9 - 20 = 28+36 - 20 = 44