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B0² = OA² + AB²
= 4² + 3²
= 16 + 9 = √25 = 5cm²
/\garis miring/\
( Note : n = garis bagi antara OC)
AB : ON = 3
OA : OB = 3
Didapati bahwa :
ΔOAB : ONB : BNC
karena OC : AB = 2 : 1
maka
OC: AB = OA : CD = OB : OD = 2:1
ΔOAB : ΔOCD
1 : 2
jadi,
OC = 2AB = 2(3) = 6
CD = 2OA = 2(4) = 8
OD = 2OB = 2(5) = 10
Atau
OD² = OC² + CD²
OD² = 6² + 8²
= 36 + 64
= √100 = 10cm²