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7'log 2 = b
7'log 3 = ab
21'log 224 = 7'log 224 / 7'log 21
= (7'log 7 + 7'log 32)/ (7'log 7 + 7'log 3)
= (1 + 7'log 2^5) / (1+ ab)
= ( 1 + 5 b)/(1+ab)