Question

Jika 2 kg air suhu 20 derajat,dicampur dg 3kg air 90 derajt,maka besar suhu campuran? [c=4200joule]....
pake cara

Answer 1

Qmasuk = Qkeluar
m₁.c₁.Δt = m₂.c₂.Δt
2 x 4200 x (t-20) = 3 x 4200 x (90-t)
8400(t-20) = 12600(90-t)
8400t - 168000 = 1134000-12600t
8400t+12600t = 1134000+168000
21000t = 1.302.000
t = 1.302.000/21.000
= 1302 / 21
= 62°C

Semoga membantu, jadikan terbaik ya !

Answer 2

M1 c (tc - 20)= m2 c (90-tc) 2.4200.(tc-20)= 3.4200(90-tc) 2(tc-20)= 3 (90- tc) 2tc -40=270-3tc 5tc=310 tc=310/5 tc= 62 drajat