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[OH-] = M. valensi basa
= 0,1 x1
= 0,1
pOH = - log [OH-]
= - log o,1
= 1 - log 1
=1
pH = 14-(pOH)
= 14-1
= 13
pH setelah pengenceran
V1 . M1 = V2 . M2
100 . 0.1 = 200 . M2
M2 = 10/200
= 0.05
[OH-] = 0,05
pOH = -log 5x10^-2
= 2 - log 5
pH = 14 - (pOH)
= 14 - (2-log 5)
= 12 + log 5